GPS模拟C语言_模拟银行c语言

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GPS模拟

# include # include # include

using namespace std;

ifstream fin(“1.txt”);//ofstream fout(“data_out.txt”);

// 1double x[5] = {-1, 0, 300, 0, 300};double y[5] = {-1, 450, 450, 0, 0};double t[5];double A, B, D,c = 2982000, p, r;double pi = 3.141592653;double xx, yy;

//三角形算法

void cal(int sign, double t1, double t2, double x1, double y1, double x2, double y2, double px, double py){

double tt1 = c * t1, tt2 = c * t2;

double q, ac;

A = x2 *(x1*x1 + y1*y1x1 *(x2*x2 + y2*y2tt1*tt1)tt2*tt2);

D = tt1 *(x2*x2 + y2*y2tt2 *(x1*x1 + y1*y1ac;

r =(x1*x1 + y1*y10)

{

switch(h)

{

case 1:

cal(-1, t[2], t[4], 300, 0, 300,-450, 0, 450);

break;

case 2: cal(-1, t[1], t[3],-300, 0,-300,-450,300, 450);

break;

case 3: cal(1, t[1], t[2], 0, 450, 300, 450, 0, 0);

break;

case 4: cal(1, t[1], t[2],-300, 450, 0, 450, 300, 0);

break;

}

break;

} } system(“pause”);return 0;声源定位

#include #include using namespace std;#define Max 50 int N=10;double xi[10];double yi[10];

double ti[10][3];double det(double a[Max][Max],int n)

{ int i,j,start;double k,temp,result=1;for(start=0;start

i=1;

while(a[start][start]==0&&start+i

{

for(j=start;j

{

temp=-1*a[start][j];

a[start][j]=a[start+i][j];

a[start+i][j]=temp;

}

i++;

}

if(start+i==n)continue;

for(i=start+1;i

{

k=a[i][start]/a[start][start];

for(j=start;j

a[i][j]=a[i][j]-k*a[start][j];

} } for(i=0;i

result*=a[i][i];return result;} int equalation(double a[Max][Max+1],double r[Max],int n)

{ double det(double a[Max][Max],int n);double det0[Max][Max],det1[Max][Max];int i,j,k;

for(i=0;i

for(j=0;j

det0[i][j]=a[i][j];if(det(det0,n)==0)return 0;

for(k=0;k

for(i=0;i

for(j=0;j

{

det0[i][j]=a[i][j];

det1[i][j]=a[i][j];

}

for(i=0;i

det1[i][k]=a[i][n];

r[k]=det(det1,n)/det(det0,n);} return 1;} double sqr(double x){ return x*x;} double g(double x,double y,double c,double xi,double yi,double ti){ return sqr(xi-x)+sqr(yi-y)-sqr(c*ti);} double fx(double x,double y,double c,int k)

{ int i;double sum=0;for(i=0;i

sum+=g(x,y,c,xi[i],yi[i],ti[i][k-1])*(xi[i]-x);return sum;} double fy(double x,double y,double c,int k)

{ int i;double sum=0;for(i=0;i

sum+=g(x,y,c,xi[i],yi[i],ti[i][k-1])*(yi[i]-y);return sum;} double fc(double x,double y,double c,int k)

{ int i;double sum=0;for(i=0;i

sum+=g(x,y,c,xi[i],yi[i],ti[i][k-1])*sqr(ti[i][k-1]);return sum;} double fxx(double x,double y,double c,int k)

{ int i;double sum=0;for(i=0;i

sum=sum-2*sqr(xi[i]-x)-g(x,y,c,xi[i],yi[i],ti[i][k-1]);return sum;} double fxy(double x,double y,double c,int k){ int i;double sum=0;for(i=0;i

sum=sum-2*(yi[i]-y)*(xi[i]-x);return sum;} double fxc(double x,double y,double c,int k){ int i;double sum=0;for(i=0;i

sum=sum-2*c*sqr(ti[i][k-1])*(xi[i]-x);return sum;} double fyx(double x,double y,double c,int k){ int i;double sum=0;for(i=0;i

sum=sum-2*(xi[i]-x)*(yi[i]-y);return sum;} double fyy(double x,double y,double c,int k)

{ int i;double sum=0;for(i=0;i

sum=sum-2*sqr(yi[i]-y)-g(x,y,c,xi[i],yi[i],ti[i][k-1]);return sum;} double fyc(double x,double y,double c,int k){ int i;double sum=0;for(i=0;i

sum=sum-2*c*sqr(ti[i][k-1])*(yi[i]-y);return sum;} double fcx(double x,double y,double c,int k){ int i;double sum=0;for(i=0;i

sum=sum-2*(xi[i]-x)*sqr(ti[i][k-1]);return sum;} double fcy(double x,double y,double c,int k){ int i;double sum=0;for(i=0;i

sum=sum-2*(yi[i]-y)*sqr(ti[i][k-1]);return sum;} double fcc(double x,double y,double c,int k){ int i;double sum=0;for(i=0;i

sum=sum-2*c*sqr(sqr(ti[i][k-1]));return sum;} int main(){ int i=0,k;double x,y,c,x0,y0,c0;double a[Max][Max+1],r[Max];freopen(“1.txt”, “r”, stdin);freopen(“1_out.txt”, “w”, stdout);

for(i=0;i

} cin>>xi[i]>>yi[i];xi[i] /= 10;yi[i] /= 10;

cin>>ti[i][0]>>ti[i][1]>>ti[i][2];for(k=1;k>x>>y;

c=0.2;do {

x0=x;y0=y;c0=c;i++;

a[0][0]=fxx(x,y,c,k);a[0][1]=fxy(x,y,c,k);a[0][2]=fxc(x,y,c,k);a[1][0]=fyx(x,y,c,k);a[1][1]=fyy(x,y,c,k);a[1][2]=fyc(x,y,c,k);a[2][0]=fcx(x,y,c,k);a[2][1]=fcy(x,y,c,k);a[2][2]=fcc(x,y,c,k);a[0][3]=x*a[0][0]+y*a[0][1]+c*a[0][2]-fx(x,y,c,k);a[1][3]=x*a[1][0]+y*a[1][1]+c*a[1][2]-fy(x,y,c,k);a[2][3]=x*a[2][0]+y*a[2][1]+c*a[2][2]-fc(x,y,c,k);

if(equalation(a,r,3)==0){

cout

return 0;

}

x=r[0];y=r[1];c=r[2];} while(abs(x-x0)+abs(y-y0)+abs(c-c0)>=1e-6);cout

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